转义引号和双引号

如何正确转义下面命令行中 -param值中的引号？

$cmd="\\server\toto.exe -batch=B -param="sort1;parmtxt='Security ID=1234'""
Invoke-Expression $cmd

这当然失败了。我尝试使用转义字符‘来转义引号(单引号和双引号) ，并且做了各种组合，但是都没有用。

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最佳答案

Escaping parameters like that is usually source of frustration and feels a lot like a time wasted. I see you're on v2 so I would suggest using a technique that Joel "Jaykul" Bennet blogged about a while ago.

Long story short: you just wrap your string with @' ... '@ :

Start-Process \\server\toto.exe @'
-batch=B -param="sort1;parmtxt='Security ID=1234'"
'@

(Mind that I assumed which quotes are needed, and which things you were attempting to escape.) If you want to work with the output, you may want to add the -NoNewWindow switch.

BTW: this was so important issue that since v3 you can use --% to stop the PowerShell parser from doing anything with your parameters:

\\server\toto.exe --% -batch=b -param="sort1;paramtxt='Security ID=1234'"

... should work fine there (with the same assumption).

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Using the backtick (`) works fine for me if I put them in the following places:

$cmd="\\server\toto.exe -batch=B -param=`"sort1;parmtxt='Security ID=1234'`""

$cmd returns as:

\\server\toto.exe -batch=B -param="sort1;parmtxt='Security ID=1234'"

Is that what you were looking for?

The error PowerShell gave me referred to an unexpected token 'sort1', and that's how I determined where to put the backticks.

The @' ... '@ syntax is called a "here string" and will return exactly what is entered. You can also use them to populate variables in the following fashion:

$cmd=@'
"\\server\toto.exe -batch=B -param="sort1;parmtxt='Security ID=1234'""
'@

The opening and closing symbols must be on their own line as shown above.

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I found myself in a similar predicament today while trying to run a command through a Node.js module:

I was using the PowerShell and trying to run:

command -e 'func($a)'

But with the extra symbols, PowerShell was mangling the arguments. To fix, I back-tick escaped double-quote marks:

command -e `"func($a)`"
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In Powershell 5 escaping double quotes can be done by backtick (`). But sometimes you need to provide your double quotes escaped which can be done by backslash + backtick (\`). Eg in this curl call:

C:\Windows\System32\curl.exe -s -k -H "Content-Type: application/json" -XPOST localhost:9200/index_name/inded_type -d"{\`"velocity\`":3.14}"

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