在 Linux/Bash 中随机移动行

我有一些文件在 linux。例如2，我需要洗牌的文件在一个文件。

比如说

$cat file1
line 1
line 2
line 3
line 4
line 5
line 6
line 7
line 8

还有

$cat file2
linea one
linea two
linea three
linea four
linea five
linea six
linea seven
linea eight

之后我整理了两个文件，我可以得到这样的东西:

linea eight
line 4
linea five
line 1
linea three
line 8
linea seven
line 5
linea two
linea one
line 2
linea four
line 7
linea six
line 1
line 6
79822 次浏览
小开

You should use shuf command =)

cat file1 file2 | shuf

Or with Perl :

cat file1 file2 | perl -MList::Util=shuffle -wne 'print shuffle <>;'
小开

I would use shuf too.

another option, gnu sort has:

   -R, --random-sort
sort by random hash of keys

you could try:

cat file1 file2|sort -R
小开

Sort: (similar lines will be put together) 

cat file1 file2 | sort -R

Shuf:

cat file1 file2 | shuf

Perl:

cat file1 file2 | perl -MList::Util=shuffle -e 'print shuffle<STDIN>'

BASH:

cat file1 file2 | while IFS= read -r line
do
printf "%06d %s\n" $RANDOM "$line"
done | sort -n | cut -c8-

Awk:

cat file1 file2 | awk 'BEGIN{srand()}{printf "%06d %s\n", rand()*1000000, $0;}' | sort -n | cut -c8-
小开

Just a note to OS X users who use MacPorts: the shuf command is part of coreutils and is installed under name gshuf.

$ sudo port install coreutils
$ gshuf example.txt # or cat example.txt | gshuf
小开

This worked for me. It employs the Fisher-Yates shuffle.

randomize()
{
arguments=("$@")
declare -a out
i="$#"
j="0"


while [[ $i -ge "0" ]] ; do
which=$(random_range "0" "$i")
out[j]=${arguments[$which]}
arguments[!which]=${arguments[i]}
(( i-- ))
(( j++ ))
done
echo ${out[*]}
}




random_range()
{
low=$1
range=$(($2 - $1))
if [[ range -ne 0 ]]; then
echo $(($low+$RANDOM % $range))
else
echo "$1"
fi
}
小开

Here's a one-liner that doesn't rely on shuf or sort -R, which I didn't have on my mac:

while read line; do echo $RANDOM $line; done < my_file | sort -n | cut -f2- -d' '

This iterates over all the lines in my_file and reprints them in a randomized order.

小开

You don't need to use pipes here. Sort alone does this with the file(s) as parameters. I would just do

sort -R file1

or if you have multiple files

sort -R file1 file2
小开

It is clearly biased rand (like half the time the list will start with the first line) but for some basic randomization with just bash builtins I guess it is fine? Just print each line yes/no then print the rest...

shuffle() {
local IFS=$'\n' tail=
while read l; do
if [ $((RANDOM%2)) = 1 ]; then
echo "$l"
else
tail="${tail}\n${l}"


fi
done < $1
printf "${tail}\n"
}

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