如何将 NSInteger 转换为 int？

例如，当向 NSInteger实例传递 value消息时，如下所示

它会导致 EXC _ BAD _ ACCESS。

那么如何将 NSInteger转换成 int呢？

如果是相关的，则只使用小于32的数字。

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最佳答案

Ta da:

NSInteger myInteger = 42;
int myInt = (int) myInteger;

NSInteger is nothing more than a 32/64 bit int. (it will use the appropriate size based on what OS/platform you're running)

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I'm not sure about the circumstances where you need to convert an NSInteger to an int.

NSInteger is just a typedef:

NSInteger Used to describe an integer independently of whether you are building for a 32-bit or a 64-bit system.

#if __LP64__ || TARGET_OS_EMBEDDED || TARGET_OS_IPHONE || TARGET_OS_WIN32 || NS_BUILD_32_LIKE_64
typedef long NSInteger;
#else
typedef int NSInteger;
#endif

You can use NSInteger any place you use an int without converting it.

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If you want to do this inline, just cast the NSUInteger or NSInteger to an int:

int i = -1;
NSUInteger row = 100;
i > row // true, since the signed int is implicitly converted to an unsigned int
i > (int)row // false

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Commonly used in UIsegmentedControl, "error" appear when compiling in 64bits instead of 32bits, easy way for not pass it to a new variable is to use this tips, add (int):

[_monChiffre setUnite:(int)[_valUnites selectedSegmentIndex]];

instead of :

[_monChiffre setUnite:[_valUnites selectedSegmentIndex]];