正则表达式匹配 URL 行尾或“/”字符

我有一个 网址，我正在尝试将它与一个正则表达式进行匹配，以获得一些组。我遇到的问题是，URL 可以以“/”结束 或者，也可以以更多的 URL 文本结束。我想匹配这样的 URL:

但不是这样的:

所以，我想我最好的选择是这样的:

/(.+)/(\d{4}-\d{2}-\d{2})-(\d+)[/$]

其中最后的字符类包含“/”或行尾。但是字符类似乎并不满意这里的“ $”。我如何才能最好地区分这些 URL，同时仍然拉回正确的组？

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最佳答案 
/(.+)/(\d{4}-\d{2}-\d{2})-(\d+)(/.*)?$

1st Capturing Group (.+)

.+ matches any character (except for line terminators)

  • + Quantifier — Matches between one and unlimited times, as many times as possible, giving back as needed (greedy)

2nd Capturing Group (\d{4}-\d{2}-\d{2})

\d{4} matches a digit (equal to [0-9])

  • {4} Quantifier — Matches exactly 4 times

- matches the character - literally (case sensitive)

\d{2} matches a digit (equal to [0-9])

  • {2} Quantifier — Matches exactly 2 times

- matches the character - literally (case sensitive)

\d{2} matches a digit (equal to [0-9])

  • {2} Quantifier — Matches exactly 2 times

- matches the character - literally (case sensitive)

3rd Capturing Group (\d+)

\d+ matches a digit (equal to [0-9])

  • + Quantifier — Matches between one and unlimited times, as many times as possible, giving back as needed (greedy)

4th Capturing Group (.*)?

? Quantifier — Matches between zero and one times, as many times as possible, giving back as needed (greedy)

.* matches any character (except for line terminators)

  • * Quantifier — Matches between zero and unlimited times, as many times as possible, giving back as needed (greedy)

$ asserts position at the end of the string

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To match either / or end of content, use (/|\z)

This only applies if you are not using multi-line matching (i.e. you're matching a single URL, not a newline-delimited list of URLs).


To put that with an updated version of what you had:

/(\S+?)/(\d{4}-\d{2}-\d{2})-(\d+)(/|\z)

Note that I've changed the start to be a non-greedy match for non-whitespace ( \S+? ) rather than matching anything and everything ( .* )

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You've got a couple regexes now which will do what you want, so that's adequately covered.

What hasn't been mentioned is why your attempt won't work: Inside a character class, $ (as well as ^, ., and /) has no special meaning, so [/$] matches either a literal / or a literal $ rather than terminating the regex (/) or matching end-of-line ($).

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In Ruby and Bash, you can use $ inside parentheses.

/(\S+?)/(\d{4}-\d{2}-\d{2})-(\d+)(/|$)

(This solution is similar to Pete Boughton's, but preserves the usage of $, which means end of line, rather than using \z, which means end of string.)


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