为什么“ True = = False is False”等于“ False”？

对于一个与 ==一起工作但与 is不一起工作的表达式，我得到了一些意想不到的行为:

>>> (True == False) is False
True
>>> True == (False is False)
True
>>> True == False is False
False
>>> id(True)
8978640
>>> id(False)
8978192
>>> id(True == False)
8978192
>>> id(False is False)
8978640
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最佳答案

Because in fact that's a chained comparison, so

True == False is False

is equivalent to

(True == False) and (False is False)

This can be surprising in this case, but lets you write 1 <= x < 4 unlike in other languages like C.

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True == False is False is a chained comparison, which means the same as (True == False) and (False is False). Since the first comparison (True==False) is false, the result of the chained comparison is False.

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From the documentation:

5.9. Comparisons

Unlike C, all comparison operations in Python have the same priority, which is lower than that of any arithmetic, shifting or bitwise operation. Also unlike C, expressions like a < b < c have the interpretation that is conventional in mathematics:

comparison    ::=  or_expr ( comp_operator or_expr )*
comp_operator ::=  "<" | ">" | "==" | ">=" | "<=" | "<>" | "!="
| "is" ["not"] | ["not"] "in"
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From the docs:

x < y <= z is equivalent to x < y and y <= z, except that y is evaluated only once (but in both cases z is not evaluated at all when x < y is found to be false).

In your case True == False is False is equivalent to True == False and False is False as the first condition is False so it short-circuits and return False.

>>> dis.dis(lambda : True == False is False)
1           0 LOAD_GLOBAL              0 (True)
3 LOAD_GLOBAL              1 (False)
6 DUP_TOP
7 ROT_THREE
8 COMPARE_OP               2 (==)
11 JUMP_IF_FALSE_OR_POP    21          <---------this step
14 LOAD_GLOBAL              1 (False)
17 COMPARE_OP               8 (is)
20 RETURN_VALUE
>>   21 ROT_TWO
22 POP_TOP
23 RETURN_VALUE

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