访问 JSON 元素

我正在从一个网址获取天气信息。

weather = urllib2.urlopen('url')
wjson = weather.read()

我得到的答案是:

{
"data": {
"current_condition": [{
"cloudcover": "0",
"humidity": "54",
"observation_time": "08:49 AM",
"precipMM": "0.0",
"pressure": "1025",
"temp_C": "10",
"temp_F": "50",
"visibility": "10",
"weatherCode": "113",
"weatherDesc": [{
"value": "Sunny"
}],
"weatherIconUrl": [{
"value": "http:\/\/www.worldweatheronline.com\/images\/wsymbols01_png_64\/wsymbol_0001_sunny.png"
}],
"winddir16Point": "E",
"winddirDegree": "100",
"windspeedKmph": "22",
"windspeedMiles": "14"
}]
}
}

我如何访问任何我想要的元素?

如果我这样做: print wjson['data']['current_condition']['temp_C']我得到错误说:

字符串索引必须是整数,而不是 str。

317172 次浏览
import json
weather = urllib2.urlopen('url')
wjson = weather.read()
wjdata = json.loads(wjson)
print wjdata['data']['current_condition'][0]['temp_C']

What you get from the url is a json string. And your can't parse it with index directly. You should convert it to a dict by json.loads and then you can parse it with index.

Instead of using .read() to intermediately save it to memory and then read it to json, allow json to load it directly from the file:

wjdata = json.load(urllib2.urlopen('url'))

Here's an alternative solution using requests:

import requests
wjdata = requests.get('url').json()
print wjdata['data']['current_condition'][0]['temp_C']

'temp_C' is a key inside dictionary that is inside a list that is inside a dictionary

This way works:

wjson['data']['current_condition'][0]['temp_C']
>> '10'

Another alternative way using get method with requests:

import requests
wjdata = requests.get('url').json()
print wjdata.get('data').get('current_condition')[0].get('temp_C')

You can do it this way too:

MYJSON = {
'username': 'gula_gut',
'pics': '/0/myfavourite.jpeg',
'id': '1'
}


#changing username
MYJSON['username'] = 'calixto'
print(MYJSON['username'])
import json


# some JSON:
json_str =  '{ "name":"Sarah", "age":25, "city":"Chicago"}'


# parse json_str:
json = json.loads(json_str)


# get tags from json
tags = []
for tag in json:
tags.append(tag)
  



# print each tag name e your content
for i in range(len(tags)):
print(tags[i] + ': ' + str(json[tags[i]]))

I did this method for in-depth navigation of a Json

def filter_dict(data: dict, extract):
try:
if isinstance(extract, list):
while extract:
if result := filter_dict(data, extract.pop(0)):
return result
shadow_data = data.copy()
for key in extract.split('.'):
if str(key).isnumeric():
key = int(key)
shadow_data = shadow_data[key]
return shadow_data
except (IndexError, KeyError, AttributeError, TypeError):
return None


filter_dict(wjdata, 'data.current_condition.0.temp_C')
# 10


Using the multiple fields:
filter_dict(wjdata, ['data.current_condition.0.temp_C', 'data.current_condition.1.temp_C']) This working as a OR when take the first element found


# 10


Like other answers have pointed out, the accepted answer to this question seems to ignore the data structure misunderstanding of the original poster.

The main issue seems to be that the original solution treats the JSON purely as a dictionary, when in fact it is a...

dictionary within a list, within a dictionary, within a dictionary

Thus, ['data'] is required to access the top-level key:value pair of the dictionary, ['current_conditions'] accesses the next level of dictionary, then [0] must be used to access the first element of the list (which has only 1 element).

Only then can ['temp_C'] be used to access the actual value for that key and retrieve the data.

x={
"data": {
"current_condition":
[{
"cloudcover": "0",
"humidity": "54",
"observation_time": "08:49 AM",
"precipMM": "0.0",
"pressure": "1025",
"temp_C": "10",
"temp_F": "50",
"visibility": "10",
"weatherCode": "113",
"weatherDesc":
[{
"value": "Sunny"
}],
                    

"weatherIconUrl":
[{
"value": "http:\/\/www.worldweatheronline.com\/images\/wsymbols01_png_64\/wsymbol_0001_sunny.png"
}],
"winddir16Point": "E",
"winddirDegree": "100",
"windspeedKmph": "22",
"windspeedMiles": "14"
},
{
"cloudcover": "0",
"humidity": "54",
"observation_time": "08:49 AM",
"precipMM": "0.0",
"pressure": "1025",
"temp_C": "5",
"temp_F": "50",
"visibility": "10",
"weatherCode": "113",
"weatherDesc":
[{
"value": "Sunny"
}],
                    

"weatherIconUrl":
[{
"value": "http:\/\/www.worldweatheronline.com\/images\/wsymbols01_png_64\/wsymbol_0001_sunny.png"
}],
"winddir16Point": "E",
"winddirDegree": "100",
"windspeedKmph": "22",
"windspeedMiles": "14"
}    ]
}
}




print(x['data']['current_condition'][0]['weatherDesc'][0]['value'])


# results in 'Sunny'

In answer to another question in comments,

"Is there a way to do this without knowing the index, assuming there were more current condition entries?"

Assuming numerous current_condition entries it is unlikely that you would just want one value, or if you do then you'll likely have another piece of information to locate that specific value (i.e. location or something).

Assuming you data set is named x, i.e. x = {"data": ...}.

If you want all of the current_condition entries you can loop through the list (of current_conditions) using:

y = []


for index in range(0,len(x['data']['current_condition']))
y.append(x['data']['current_condition'][index]['temp_C'])