Should be possible using two statements within one transaction, an insert and a delete:
BEGIN TRANSACTION;
INSERT INTO Table2 (<columns>)
SELECT <columns>
FROM Table1
WHERE <condition>;
DELETE FROM Table1
WHERE <condition>;
COMMIT;
This is the simplest form. If you have to worry about new matching records being inserted into table1 between the two statements, you can add an and exists <in table2>.
All these answers run the same query for the INSERT and DELETE. As mentioned previously, this risks the DELETE picking up records inserted between statements and could be slow if the query is complex (although clever engines "should" make the second call fast).
The correct way (assuming the INSERT is into a fresh table) is to do the DELETE against table1 using the key field of table2.
The delete should be:
DELETE FROM tbl_OldTableName WHERE id in (SELECT id FROM tbl_NewTableName)
Excuse my syntax, I'm jumping between engines but you get the idea.
This is an ancient post, sorry, but I only came across it now and I wanted to give my solution to whoever might stumble upon this one day.
As some have mentioned, performing an INSERT and then a DELETE might lead to integrity issues, so perhaps a way to get around it, and to perform everything neatly in a single statement, is to take advantage of the [deleted] temporary table.
DELETE FROM [source]
OUTPUT [deleted].<column_list>
INTO [destination] (<column_list>)
WITH deleted_rows AS (
DELETE FROM source_table WHERE id = 1
RETURNING *
)
INSERT INTO destination_table
SELECT * FROM deleted_rows;
EXAMPLE:
postgres=# select * from test1 ;
id | name
----+--------
1 | yogesh
2 | Raunak
3 | Varun
(3 rows)
postgres=# select * from test2;
id | name
----+------
(0 rows)
postgres=# WITH deleted_rows AS (
postgres(# DELETE FROM test1 WHERE id = 1
postgres(# RETURNING *
postgres(# )
postgres-# INSERT INTO test2
postgres-# SELECT * FROM deleted_rows;
INSERT 0 1
postgres=# select * from test2;
id | name
----+--------
1 | yogesh
(1 row)
postgres=# select * from test1;
id | name
----+--------
2 | Raunak
3 | Varun
You may use "Logical Partitioning" to switch data between tables:
By updating the Partition Column, data will be automatically moved to the other table:
here is the sample:
CREATE TABLE TBL_Part1
(id INT NOT NULL,
val VARCHAR(10) NULL,
PartitionColumn VARCHAR(10) CONSTRAINT CK_Part1 CHECK(PartitionColumn = 'TBL_Part1'),
CONSTRAINT TBL_Part1_PK PRIMARY KEY(PartitionColumn, id)
);
CREATE TABLE TBL_Part2
(id INT NOT NULL,
val VARCHAR(10) NULL,
PartitionColumn VARCHAR(10) CONSTRAINT CK_Part2 CHECK(PartitionColumn = 'TBL_Part2'),
CONSTRAINT TBL_Part2_PK PRIMARY KEY(PartitionColumn, id)
);
GO
CREATE VIEW TBL(id, val, PartitionColumn)
WITH SCHEMABINDING
AS
SELECT id, val, PartitionColumn FROM dbo.TBL_Part1
UNION ALL
SELECT id, val, PartitionColumn FROM dbo.TBL_Part2;
GO
--Insert sample to TBL ( will be inserted to Part1 )
INSERT INTO TBL
VALUES(1, 'rec1', 'TBL_Part1');
INSERT INTO TBL
VALUES(2, 'rec2', 'TBL_Part1');
GO
--Query sub table to verify
SELECT * FROM TBL_Part1
GO
--move the data to table TBL_Part2 by Logical Partition switching technique
UPDATE TBL
SET
PartitionColumn = 'TBL_Part2';
GO
--Query sub table to verify
SELECT * FROM TBL_Part2