XSLT 可以插入当前日期吗？

我们办公室使用的一个程序通过将 XSLT 文件导出的 XML 文件翻译成 XHTML 来导出报告。我正在重写 XSLT，以更改格式，并从源 XML 文件中添加更多信息。

我希望在最终报告中包括文件创建的日期。但是当前的日期/时间不包含在原始的 XML 文件中，对于如何创建 XML 文件，我也没有任何控制权。XSLT 中似乎没有构建任何返回当前日期的日期函数。

有人知道我如何在 XSLT 转换期间包含当前日期吗？

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最佳答案

XSLT 2

Date functions are available natively, such as:

<xsl:value-of  select="current-dateTime()"/>

There is also current-date() and current-time().

XSLT 1

Use the EXSLT date and times extension package.

  1. Download the date and times package from GitHub.
  2. Extract date.xsl to the location of your XSL files.
  3. Set the stylesheet header.
  4. Import date.xsl.

For example:

<xsl:stylesheet version="1.0"
xmlns:date="http://exslt.org/dates-and-times"
extension-element-prefixes="date"
...>


<xsl:import href="date.xsl" />


<xsl:template match="//root">
<xsl:value-of select="date:date-time()"/>
</xsl:template>
</xsl:stylesheet>

小开

For MSXML parser, try this:

<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:msxsl="urn:schemas-microsoft-com:xslt"
xmlns:my="urn:sample" extension-element-prefixes="msxsl">


<msxsl:script language="JScript" implements-prefix="my">
function today()
{
return new Date();
}
</msxsl:script>
<xsl:template match="/">
    

Today = <xsl:value-of select="my:today()"/>
    

</xsl:template>
</xsl:stylesheet>

Also read XSLT Stylesheet Scripting using msxsl:script and Extending XSLT with JScript, C#, and Visual Basic .NET

小开

Do you have control over running the transformation? If so, you could pass in the current date to the XSL and use $current-date from inside your XSL. Below is how you declare the incoming parameter, but with knowing how you are running the transformation, I can't tell you how to pass in the value.

<xsl:param name="current-date" />

For example, from the bash script, use:

xsltproc --stringparam current-date `date +%Y-%m-%d` -o output.html path-to.xsl path-to.xml

Then, in the xsl you can use:

<xsl:value-of select="$current-date"/>
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...
xmlns:msxsl="urn:schemas-microsoft-com:xslt"
xmlns:local="urn:local" extension-element-prefixes="msxsl">


<msxsl:script language="CSharp" implements-prefix="local">
public string dateTimeNow()
{
return DateTime.Now.ToString("yyyy-MM-ddTHH:mm:ssZ");
}
</msxsl:script>
...
<xsl:value-of select="local:dateTimeNow()"/>
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format-date(current-date(), '[M01]/[D01]/[Y0001]') = 09/19/2013
format-time(current-time(), '[H01]:[m01] [z]') = 09:26 GMT+10
format-dateTime(current-dateTime(), '[h1]:[m01] [P] on [MNn] [D].') = 9:26 a.m. on September 19.

reference: Formatting Dates and Times using XSLT 2.0 and XPath

小开

Late answer, but my solution works in Eclipse XSLT. Eclipse uses XSLT 1 at time of this writing. You can install an XSLT 2 engine like Saxon. Or you can use the XSLT 1 solution below to insert current date and time.

<xsl:value-of select="java:util.Date.new()"/>

This will call Java's Data class to output the date. It will not work unless you also put the following "java:" definition in your <xsl:stylesheet> tag.

<xsl:stylesheet [...snip...]
xmlns:java="java"
[...snip...]>

I hope that helps someone. This simple answer was difficult to find for me.


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