SQL: 只大写第一个字母

我需要一个 SQL 语句大写每个单词的第一个字母。其他字符必须是小写字母。

单词可以是这样的:

wezembeek-oppem
roeselare
BRUGGE
louvain-la-neuve

也就是说:

Wezembeek-Oppem
Roeselare
Brugge
Louvain-La-Neuve

这应该是一个 UPDATE 语句，我想更新一个列的数据。 非常感谢您的提前回答，我是一个 SQL 新手。

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最佳答案

您是要求重命名列本身还是将列内的数据大写？如果你必须更改它的数据，那么使用以下方法:

UPDATE [yourtable]
SET word=UPPER(LEFT(word,1))+LOWER(SUBSTRING(word,2,LEN(word)))

如果只是为了显示而更改，而不需要更改表中的实际数据:

SELECT UPPER(LEFT(word,1))+LOWER(SUBSTRING(word,2,LEN(word))) FROM [yourtable]

希望这个能帮上忙。

编辑: 我意识到了“-”，所以这里是我尝试用函数来解决这个问题。

CREATE FUNCTION [dbo].[CapitalizeFirstLetter]
(
--string need to format
@string VARCHAR(200)--increase the variable size depending on your needs.
)
RETURNS VARCHAR(200)
AS


BEGIN
--Declare Variables
DECLARE @Index INT,
@ResultString VARCHAR(200)--result string size should equal to the @string variable size
--Initialize the variables
SET @Index = 1
SET @ResultString = ''
--Run the Loop until END of the string


WHILE (@Index <LEN(@string)+1)
BEGIN
IF (@Index = 1)--first letter of the string
BEGIN
--make the first letter capital
SET @ResultString =
@ResultString + UPPER(SUBSTRING(@string, @Index, 1))
SET @Index = @Index+ 1--increase the index
END


-- IF the previous character is space or '-' or next character is '-'


ELSE IF ((SUBSTRING(@string, @Index-1, 1) =' 'or SUBSTRING(@string, @Index-1, 1) ='-' or SUBSTRING(@string, @Index+1, 1) ='-') and @Index+1 <> LEN(@string))
BEGIN
--make the letter capital
SET
@ResultString = @ResultString + UPPER(SUBSTRING(@string,@Index, 1))
SET
@Index = @Index +1--increase the index
END
ELSE-- all others
BEGIN
-- make the letter simple
SET
@ResultString = @ResultString + LOWER(SUBSTRING(@string,@Index, 1))
SET
@Index = @Index +1--incerase the index
END
END--END of the loop


IF (@@ERROR
<> 0)-- any error occur return the sEND string
BEGIN
SET
@ResultString = @string
END
-- IF no error found return the new string
RETURN @ResultString
END

那么密码就是:

UPDATE [yourtable]
SET word=dbo.CapitalizeFirstLetter([STRING TO GO HERE])
小开 
select replace(wm_concat(new),',','-') exp_res from (select distinct initcap(substr(name,decode(level,1,1,instr(name,'-',1,level-1)+1),decode(level,(length(name)-length(replace(name,'-','')))+1,9999,instr(name,'-',1,level)-1-decode(level,1,0,instr(name,'-',1,level-1))))) new from table;
connect by level<= (select (length(name)-length(replace(name,'-','')))+1 from table));
小开

创建以下函数

Alter FUNCTION InitialCap(@String VARCHAR(8000))
RETURNS VARCHAR(8000)
AS
BEGIN


DECLARE @Position INT;


SELECT @String   = STUFF(LOWER(@String),1,1,UPPER(LEFT(@String,1))) COLLATE Latin1_General_Bin,
@Position = PATINDEX('%[^A-Za-z''][a-z]%',@String COLLATE Latin1_General_Bin);


WHILE @Position > 0
SELECT @String   = STUFF(@String,@Position,2,UPPER(SUBSTRING(@String,@Position,2))) COLLATE Latin1_General_Bin,
@Position = PATINDEX('%[^A-Za-z''][a-z]%',@String COLLATE Latin1_General_Bin);


RETURN @String;
END ;

那就这么说吧

select dbo.InitialCap(columnname) from yourtable
小开

请在不使用函数的情况下检查查询:

declare @T table(Insurance varchar(max))


insert into @T values ('wezembeek-oppem')
insert into @T values ('roeselare')
insert into @T values ('BRUGGE')
insert into @T values ('louvain-la-neuve')


select (
select upper(T.N.value('.', 'char(1)'))+
lower(stuff(T.N.value('.', 'varchar(max)'), 1, 1, ''))+(CASE WHEN RIGHT(T.N.value('.', 'varchar(max)'), 1)='-' THEN '' ELSE ' ' END)
from X.InsXML.nodes('/N') as T(N)
for xml path(''), type
).value('.', 'varchar(max)') as Insurance
from
(
select cast('<N>'+replace(
replace(
Insurance,
' ', '</N><N>'),
'-', '-</N><N>')+'</N>' as xml) as InsXML
from @T
) as X

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