等待进程，直到所有子进程完成？

我有一个主进程，它创建两个或更多的子进程，我希望主进程等待，直到所有子进程完成其操作和退出？

 # main_script.py


p1 = subprocess.Popen(['python script1.py'])
p2 = subprocess.Popen(['python script2.py'])
...
#wait main process until both p1, p2 finish
...
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subprocess.call

Automatically waits , you can also use:

p1.wait()
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最佳答案

A Popen object has a .wait() method exactly defined for this: to wait for the completion of a given subprocess (and, besides, for retuning its exit status).

If you use this method, you'll prevent that the process zombies are lying around for too long.

(Alternatively, you can use subprocess.call() or subprocess.check_call() for calling and waiting. If you don't need IO with the process, that might be enough. But probably this is not an option, because your if the two subprocesses seem to be supposed to run in parallel, which they won't with (call()/check_call().)

If you have several subprocesses to wait for, you can do

exit_codes = [p.wait() for p in p1, p2]

(or maybe exit_codes = [p.wait() for p in (p1, p2)] for syntactical reasons)

which returns as soon as all subprocesses have finished. You then have a list of return codes which you maybe can evaluate.


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