“元素”的初始化被“ case”标签跳过

我不明白为什么我会得到这个错误:

“元素”的初始化被“ case”标签跳过。

有人能给我解释一下吗？

void LinkedList::process_example(int choice) {
switch(choice) {
case 1:
cout << endl << endl << "Current S = ";
this->printSet();


cout << "Enter an element :";
char* element = "lol";


//cin>>element;
cin.clear();
cin.ignore(200, '\n');


this->Addelementfromback(element); //error is here
cout << endl << endl << "Current S = ";


this->printSet();
break;


case 2:
this->check_element();
break;


case 3:
cout << endl << endl;
cout << "Current Set S = ";
this->printSet();


cout << endl << "S has ";
int count = this ->check_cardinality();
cout << count << " elements";
break;
}
}

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最佳答案

Try wrap case with {}, and put all your statement inside {}.

case 1:
{
cout << endl << endl << "Current S = ";
this->printSet();
// and other mess
}
break;

You should put all these statement in functions, keep case statement clear. For example, write this style:

case 1:
initializeElement();
break;
case 2:
doSomethingElse();
break;

See link

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When a variable is declared in one case, the next case is technically still in the same scope so you could reference it there but if you hit that case without hitting this one first you would end up calling an uninitialised variable. This error prevents that.

All you need to do is either define it before the switch statement or use curly braces { } to make sure it goes out of scope before exiting a specific case.