在 PHP 中什么是意外的 T_VARIABLE？

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It could be some other line as well. PHP is not always that exact.

Probably you are just missing a semicolon on previous line.

How to reproduce this error, put this in a file called a.php:

<?php
$a = 5
$b = 7;        // Error happens here.
print $b;
?>

Run it:

eric@dev ~ $ php a.php


PHP Parse error:  syntax error, unexpected T_VARIABLE in
/home/el/code/a.php on line 3

Explanation:

The PHP parser converts your program to a series of tokens. A T_VARIABLE is a Token of type VARIABLE. When the parser processes tokens, it tries to make sense of them, and throws errors if it receives a variable where none is allowed.

In the simple case above with variable $b, the parser tried to process this:

$a = 5 $b = 7;

The PHP parser looks at the $b after the 5 and says "that is unexpected".

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最佳答案

There might be a semicolon or bracket missing a line before your pasted line.

It seems fine to me; every string is allowed as an array index.

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In my case it was an issue of the PHP version.

The .phar file I was using was not compatible with PHP 5.3.9. Switching interpreter to PHP 7 did fix it.