如何在.NET 中将 int []连接到以字符分隔的字符串?

我有一个整数数组:

int[] number = new int[] { 2,3,6,7 };

将这些数字转换成单个字符串的最简单方法是什么(如: "2,3,6,7") ?

我使用的是 C # 和.NET 3.5。

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var ints = new int[] {1, 2, 3, 4, 5};
var result = string.Join(",", ints.Select(x => x.ToString()).ToArray());
Console.WriteLine(result); // prints "1,2,3,4,5"

As of (at least) .NET 4.5,

var result = string.Join(",", ints.Select(x => x.ToString()).ToArray());

is equivalent to:

var result = string.Join(",", ints);

I see several solutions advertise usage of StringBuilder. Someone complains that the Join method should take an IEnumerable argument.

I'm going to disappoint you :) String.Join requires an array for a single reason - performance. The Join method needs to know the size of the data to effectively preallocate the necessary amount of memory.

Here is a part of the internal implementation of String.Join method:

// length computed from length of items in input array and length of separator
string str = FastAllocateString(length);
fixed (char* chRef = &str.m_firstChar) // note than we use direct memory access here
{
UnSafeCharBuffer buffer = new UnSafeCharBuffer(chRef, length);
buffer.AppendString(value[startIndex]);
for (int j = startIndex + 1; j <= num2; j++)
{
buffer.AppendString(separator);
buffer.AppendString(value[j]);
}
}
String.Join(";", number.Select(item => item.ToString()).ToArray());

We have to convert each of the items to a String before we can join them, so it makes sense to use Select and a lambda expression. This is equivalent to map in some other languages. Then we have to convert the resulting collection of string back to an array, because String.Join only accepts a string array.

The ToArray() is slightly ugly I think. String.Join should really accept IEnumerable<String>, there is no reason to restrict it to only arrays. This is probably just because Join is from before generics, when arrays were the only kind of typed collection available.

If your array of integers may be large, you'll get better performance using a StringBuilder. E.g.:

StringBuilder builder = new StringBuilder();
char separator = ',';
foreach(int value in integerArray)
{
if (builder.Length > 0) builder.Append(separator);
builder.Append(value);
}
string result = builder.ToString();

Edit: When I posted this I was under the mistaken impression that "StringBuilder.Append(int value)" internally managed to append the string representation of the integer value without creating a string object. This is wrong: inspecting the method with Reflector shows that it simply appends value.ToString().

Therefore the only potential performance difference is that this technique avoids one array creation, and frees the strings for garbage collection slightly sooner. In practice this won't make any measurable difference, so I've upvoted this better solution.

One mixture of the two approaches would be to write an extension method on IEnumerable<T> which used a StringBuilder. Here's an example, with different overloads depending on whether you want to specify the transformation or just rely on plain ToString. I've named the method "JoinStrings" instead of "Join" to avoid confusion with the other type of Join. Perhaps someone can come up with a better name :)

using System;
using System.Collections.Generic;
using System.Text;


public static class Extensions
{
public static string JoinStrings<T>(this IEnumerable<T> source,
Func<T, string> projection, string separator)
{
StringBuilder builder = new StringBuilder();
bool first = true;
foreach (T element in source)
{
if (first)
{
first = false;
}
else
{
builder.Append(separator);
}
builder.Append(projection(element));
}
return builder.ToString();
}


public static string JoinStrings<T>(this IEnumerable<T> source, string separator)
{
return JoinStrings(source, t => t.ToString(), separator);
}
}


class Test
{


public static void Main()
{
int[] x = {1, 2, 3, 4, 5, 10, 11};


Console.WriteLine(x.JoinStrings(";"));
Console.WriteLine(x.JoinStrings(i => i.ToString("X"), ","));
}
}

I agree with the lambda expression for readability and maintainability, but it will not always be the best option. The downside to using both the IEnumerable/ToArray and StringBuilder approaches is that they have to dynamically grow a list, either of items or characters, since they do not know how much space will be needed for the final string.

If the rare case where speed is more important than conciseness, the following is more efficient.

int[] number = new int[] { 1, 2, 3, 4, 5 };
string[] strings = new string[number.Length];
for (int i = 0; i < number.Length; i++)
strings[i] = number[i].ToString();
string result = string.Join(",", strings);

You can do

ints.ToString(",")
ints.ToString("|")
ints.ToString(":")

Check out

Separator Delimited ToString for Array, List, Dictionary, Generic IEnumerable

Although the OP specified .NET 3.5, people wanting to do this in .NET 2.0 with C# 2.0 can do this:

string.Join(",", Array.ConvertAll<int, String>(ints, Convert.ToString));

I find there are a number of other cases where the use of the Convert.xxx functions is a neater alternative to a lambda, although in C# 3.0 the lambda might help the type-inferencing.

A fairly compact C# 3.0 version which works with .NET 2.0 is this:

string.Join(",", Array.ConvertAll(ints, item => item.ToString()))
ints.Aggregate("", ( str, n ) => str +","+ n ).Substring(1);

I also thought there was a simpler way.

The question is for "easiest way of converting these in to a single string where the number are separated by a character".

The easiest way is:

int[] numbers = new int[] { 2,3,6,7 };
string number_string = string.Join(",", numbers);
// do whatever you want with your exciting new number string

This only works in .NET 4.0+.

In .NET 4.0, string join has an overload for params object[], so it's as simple as:

int[] ids = new int[] { 1, 2, 3 };
string.Join(",", ids);

Example

int[] ids = new int[] { 1, 2, 3 };
System.Data.Common.DbCommand cmd = new System.Data.SqlClient.SqlCommand("SELECT * FROM some_table WHERE id_column IN (@bla)");
cmd.CommandText = cmd.CommandText.Replace("@bla",  string.Join(",", ids));

In .NET 2.0, it's a tiny little bit more difficult, since there's no such overload. So you need your own generic method:

public static string JoinArray<T>(string separator, T[] inputTypeArray)
{
string strRetValue = null;
System.Collections.Generic.List<string> ls = new System.Collections.Generic.List<string>();


for (int i = 0; i < inputTypeArray.Length; ++i)
{
string str = System.Convert.ToString(inputTypeArray[i], System.Globalization.CultureInfo.InvariantCulture);


if (!string.IsNullOrEmpty(str))
{
// SQL-Escape
// if (typeof(T) == typeof(string))
//    str = str.Replace("'", "''");


ls.Add(str);
} // End if (!string.IsNullOrEmpty(str))


} // Next i


strRetValue= string.Join(separator, ls.ToArray());
ls.Clear();
ls = null;


return strRetValue;
}

In .NET 3.5, you can use extension methods:

public static class ArrayEx
{


public static string JoinArray<T>(this T[] inputTypeArray, string separator)
{
string strRetValue = null;
System.Collections.Generic.List<string> ls = new System.Collections.Generic.List<string>();


for (int i = 0; i < inputTypeArray.Length; ++i)
{
string str = System.Convert.ToString(inputTypeArray[i], System.Globalization.CultureInfo.InvariantCulture);


if (!string.IsNullOrEmpty(str))
{
// SQL-Escape
// if (typeof(T) == typeof(string))
//    str = str.Replace("'", "''");


ls.Add(str);
} // End if (!string.IsNullOrEmpty(str))


} // Next i


strRetValue= string.Join(separator, ls.ToArray());
ls.Clear();
ls = null;


return strRetValue;
}


}

So you can use the JoinArray extension method.

int[] ids = new int[] { 1, 2, 3 };
string strIdList = ids.JoinArray(",");

You can also use that extension method in .NET 2.0, if you add the ExtensionAttribute to your code:

// you need this once (only), and it must be in this namespace
namespace System.Runtime.CompilerServices
{
[AttributeUsage(AttributeTargets.Assembly | AttributeTargets.Class | AttributeTargets.Method)]
public sealed class ExtensionAttribute : Attribute {}
}

Forget about .NET 3.5 and use the following code in .NET Core:

var result = string.Join(",", ints);