Lua 中字符串的串联

在许多语言中,您可以在变量赋值上连接字符串。我有一个场景,使用 Lua 编程语言,需要将命令的输出附加到现有变量。Lua 中是否有与下面的例子等价的函数?

其他语言的例子:

===== PERL =====
$filename = "checkbook";
$filename .= ".tmp";
================


===== C# =====
string filename = "checkbook";
filename += ".tmp";
===============
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Strings can be joined together using the concatenation operator ".."

this is the same for variables I think

Concatenation:

The string concatenation operator in Lua is denoted by two dots ('..'). If both operands are strings or numbers, then they are converted to strings according to the rules mentioned in §2.2.1. Otherwise, the "concat" metamethod is called (see §2.8).

from: http://www.lua.org/manual/5.1/manual.html#2.5.4

If you are asking whether there's shorthand version of operator .. - no there isn't. You cannot write a ..= b. You'll have to type it in full: filename = filename .. ".tmp"

As other answers have said, the string concatenation operator in Lua is two dots.

Your simple example would be written like this:

filename = "checkbook"
filename = filename .. ".tmp"

However, there is a caveat to be aware of. Since strings in Lua are immutable, each concatenation creates a new string object and copies the data from the source strings to it. That makes successive concatenations to a single string have very poor performance.

The Lua idiom for this case is something like this:

function listvalues(s)
local t = { }
for k,v in ipairs(s) do
t[#t+1] = tostring(v)
end
return table.concat(t,"\n")
end

By collecting the strings to be concatenated in an array t, the standard library routine table.concat can be used to concatenate them all up (along with a separator string between each pair) without unnecessary string copying.

Update: I just noticed that I originally wrote the code snippet above using pairs() instead of ipairs().

As originally written, the function listvalues() would indeed produce every value from the table passed in, but not in a stable or predictable order. On the other hand, it would include values who's keys were not positive integers in the span of 1 to #s. That is what pairs() does: it produces every single (key,value) pair stored in the table.

In most cases where you would be using something like listvaluas() you would be interested in preserving their order. So a call written as listvalues{13, 42, 17, 4} would produce a string containing those value in that order. However, pairs() won't do that, it will itemize them in some order that depends on the underlying implementation of the table data structure. It is known that the order not only depends on the keys, but also on the order in which the keys were inserted and other keys removed.

Of course ipairs() isn't a perfect answer either. It only enumerates those values of the table that form a "sequence". That is, those values whose keys form an unbroken block spanning from 1 to some upper bound, which is (usually) also the value returned by the # operator. (In many cases, the function ipairs() itself is better replaced by a simpler for loop that just counts from 1 to #s. This is the recommended practice in Lua 5.2 and in LuaJIT where the simpler for loop can be more efficiently implemented than the ipairs() iterator.)

If pairs() really is the right approach, then it is usually the case that you want to print both the key and the value. This reduces the concerns about order by making the data self-describing. Of course, since any Lua type (except nil and the floating point NaN) can be used as a key (and NaN can also be stored as a value) finding a string representation is left as an exercise for the student. And don't forget about trees and more complex structures of tables.

In other languages you would use:

// C#


string a = "Hello";


// 2 Options
a = a + " World!";


// or the easier way:
a += " World!";

Now in Lua: You would use .. , an example here:

-- Lua


local a = "Hello"


-- Sadly Lua doesn't have += so you have to do it this way.
a = a.." World!";