如何使用 JavaScript 获取元素的背景图像 URL?

如何在 JavaScript 中获得 <div>元素的 background-image URL? 例如,我有这个:

<div style="background-image:url('http://www.example.com/img.png');">...</div>

我如何得到 只是的网址的 background-image

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Try this:

var url = document.getElementById("divID").style.backgroundImage;
alert(url.substring(4, url.length-1));

Or, using replace:

url.replace('url(','').replace(')','');
// Or...
backgroundImage.slice(4, -1).replace(/["']/g, "");

You can try this:

var img = document.getElementById('your_div_id'),
style = img.currentStyle || window.getComputedStyle(img, false),
bi = style.backgroundImage.slice(4, -1).replace(/"/g, "");

// Get the image id, style and the url from it
var img = document.getElementById('testdiv'),
style = img.currentStyle || window.getComputedStyle(img, false),
bi = style.backgroundImage.slice(4, -1).replace(/"/g, "");


// Display the url to the user
console.log('Image URL: ' + bi);
<div id="testdiv" style="background-image:url('http://placehold.it/200x200');"></div>

Edit:

Based on @Miguel and other comments below, you can try this to remove additional quotation marks if your browser (IE/FF/Chrome...) adds it to the url:

bi = style.backgroundImage.slice(4, -1).replace(/"/g, "");

and if it may includes single quotation, use: replace(/['"]/g, "")

DEMO FIDDLE

Just to add to this in case anyone else has a similar idea, you could also use Regex:

var url = backgroundImage.match(/url\(["']?([^"']*)["']?\)/)[1];

However it seems like @Praveen's solution actually performs better in Safari and Firefox, according to jsPerf: http://jsperf.com/match-vs-slice-and-replace

If you want to account for cases where the value includes quotes but are unsure whether it's a double or single quote, you could do:

var url = backgroundImage.slice(4, -1).replace(/["']/g, "");

First of all you need to return your background-image content:

var img = $('#your_div_id').css('background-image');

This will return the URL as following:

"url('http://www.example.com/img.png')"

Then you need to remove the un-wanted parts of this URL:

img = img.replace(/(url\(|\)|")/g, '');

const regex = /background-image:url\(["']?([^"']*)["']?\)/gm;
const str = `<div style="background-image:url('http://www.example.com/img.png');">...</div>`;
let m;


while ((m = regex.exec(str)) !== null) {
// This is necessary to avoid infinite loops with zero-width matches
if (m.index === regex.lastIndex) {
regex.lastIndex++;
}
    

// The result can be accessed through the `m`-variable.
m.forEach((match, groupIndex) => {
console.log(`Found match, group ${groupIndex}: ${match}`);
});
}

Log to console all background-image URLs, without parentheses and quotes:

var element = document.getElementById('divId');
var prop = window.getComputedStyle(element).getPropertyValue('background-image');
var re = /url\((['"])?(.*?)\1\)/gi;
var matches;
while ((matches = re.exec(prop)) !== null) {
console.log(matches[2]);
}