如何从 WCF REST 方法返回自定义 HTTP状态码?

如果 WCF REST 调用中出现错误,比如没有找到所请求的资源,那么如何在 OperationContract 方法中使用 HTTP 响应代码(例如,将其设置为 HTTP 404之类的代码) ?

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There is a WebOperationContext that you can access and it has a OutgoingResponse property of type OutgoingWebResponseContext which has a StatusCode property that can be set.

WebOperationContext ctx = WebOperationContext.Current;
ctx.OutgoingResponse.StatusCode = System.Net.HttpStatusCode.OK;

For 404 there is a built in method on the WebOperationContext.Current.OutgoingResponse called SetStatusAsNotFound(string message) that will set the status code to 404 and a status description with one call.

Note there is also, SetStatusAsCreated(Uri location) that will set the status code to 201 and location header with one call.

If you need to return a reason body then have a look at WebFaultException

For example

throw new WebFaultException<string>("Bar wasn't Foo'd", HttpStatusCode.BadRequest );

If you wish to see the status description in the header, REST method should make sure to return null from the Catch() section as below:

catch (ArgumentException ex)
{
WebOperationContext.Current.OutgoingResponse.StatusCode = HttpStatusCode.InternalServerError;
WebOperationContext.Current.OutgoingResponse.StatusDescription = ex.Message;
return null;
}

This did not work for me for WCF Data Services. Instead, you can use DataServiceException in case of Data Services. Found the following post useful. http://social.msdn.microsoft.com/Forums/en/adodotnetdataservices/thread/f0cbab98-fcd7-4248-af81-5f74b019d8de

WebOperationContext.Current.OutgoingResponse.StatusCode = HttpStatusCode.Unauthorized;
throw new WebException("令牌码不正确", new InvalidTokenException());

ref:https://social.msdn.microsoft.com/Forums/en-US/f6671de3-34ce-4b70-9a77-39ecf5d1b9c3/weboperationcontext-http-statuses-and-exceptions?forum=wcf

You can also return a statuscode and reason body with WebOperationContext's StatusCode and StatusDescription:

WebOperationContext context = WebOperationContext.Current;
context.OutgoingResponse.StatusCode = HttpStatusCode.OK;
context.OutgoingResponse.StatusDescription = "Your Message";