Inconsistent accessibility: property type is less accessible

Please can someone help with the following error:

Inconsistent accessibility: property type 'Test.Delivery' is less accessible than property 'Test.Form1.thelivery' 

private Delivery thedelivery;


public Delivery thedelivery
{
get { return thedelivery; }
set { thedelivery = value; }
}

I'm not able to run the program due to the error message of inconsistency.

Here is my delivery class:

namespace Test
{
class Delivery
{
private string name;
private string address;
private DateTime arrivalTime;


public string Name
{
get { return name; }
set { name = value; }
}


public string Address
{
get { return address; }
set { address = value; }
}


public DateTime ArrivlaTime
{
get { return arrivalTime; }
set { arrivalTime = value; }
}


public string ToString()
{
{ return name + address + arrivalTime.ToString(); }
}
}
}
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小开

类 Delivery没有访问修饰符，这意味着它默认为 internal。然后，如果尝试将该类型的属性公开为 public，则不会起作用。您的类型(类)需要具有与属性相同或更高的访问权限。

更多关于访问修饰符的信息: http://msdn.microsoft.com/en-us/library/ms173121.aspx

小开

您的 Delivery类是内部的(类的默认可见性) ，但是属性(可能包含类)是公共的，因此该属性比 Delivery类更容易访问。您需要使 Delivery公开，或者限制 thelivery属性的可见性。

小开
最佳答案

使您的类 public访问修饰符,

just add public keyword infront of your class name

 namespace Test
{
public  class Delivery
{
private string name;
private string address;
private DateTime arrivalTime;


public string Name
{
get { return name; }
set { name = value; }
}


public string Address
{
get { return address; }
set { address = value; }
}


public DateTime ArrivlaTime
{
get { return arrivalTime; }
set { arrivalTime = value; }
}


public string ToString()
{
{ return name + address + arrivalTime.ToString(); }
}
}
}

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