ISO C90禁止 C 语言中的混合声明和代码

我用这种方式声明了一个变量:

int i = 0;

我收到警告:

ISO C90禁止混合声明和代码

我该怎么补救？

177908 次浏览
小开
最佳答案

I think you should move the variable declaration to top of block. I.e.

{
foo();
int i = 0;
bar();
}

to

{
int i = 0;
foo();
bar();
}
小开

Just use a compiler (or provide it with the arguments it needs) such that it compiles for a more recent version of the C standard, C99 or C11. E.g for the GCC family of compilers that would be -std=c99.

小开

Up until the C99 standard, all declarations had to come before any statements in a block:

void foo()
{
int i, j;
double k;
char *c;


// code


if (c)
{
int m, n;


// more code
}
// etc.
}

C99 allowed for mixing declarations and statements (like C++). Many compilers still default to C89, and some compilers (such as Microsoft's) don't support C99 at all.

So, you will need to do the following:

  1. Determine if your compiler supports C99 or later; if it does, configure it so that it's compiling C99 instead of C89;

  2. If your compiler doesn't support C99 or later, you will either need to find a different compiler that does support it, or rewrite your code so that all declarations come before any statements within the block.

小开

To diagnose what really triggers the error, I would first try to remove = 0

  • If the error is tripped, then most likely the declaration goes after the code.

  • If no error, then it may be related to a C-standard enforcement/compile flags OR ...something else.

In any case, declare the variable in the beginning of the current scope. You may then initialize it separately. Indeed, if this variable deserves its own scope - delimit its definition in {}.

If the OP could clarify the context, then a more directed response would follow.

小开

Make sure the variable is on the top part of the block, and in case you compile it with -ansi-pedantic, make sure it looks like this:

function() {
int i;
i = 0;


someCode();
}
小开

-Wdeclaration-after-statement minimal reproducible example

main.c

#!/usr/bin/env bash


set -eux


cat << EOF > main.c
#include <stdio.h>


int main(void) {
puts("hello");
int a = 1;
printf("%d\n", a);
return 0;
}
EOF

Give warning:

gcc -std=c89 -Wdeclaration-after-statement -Werror main.c
gcc -std=c99 -Wdeclaration-after-statement -Werror main.c
gcc -std=c89 -pedantic -Werror main.c

Don't give warning:

gcc -std=c89 -pedantic -Wno-declaration-after-statement -Werror main.c
gcc -std=c89 -Wno-declaration-after-statement -Werror main.c
gcc -std=c99 -pedantic -Werror main.c
gcc -std=c89 -Wall -Wextra -Werror main.c
# https://stackoverflow.com/questions/14737104/what-is-the-default-c-mode-for-the-current-gcc-especially-on-ubuntu/53063656#53063656
gcc -pedantic -Werror main.c

The warning:

main.c: In function ‘main’:
main.c:5:5: warning: ISO C90 forbids mixed declarations and code [-Wdeclaration-after-statement]
int a = 1;
^~~

Tested on Ubuntu 16.04, GCC 6.4.0.

小开

Ensure you made your declarations before any statements in the block. For instance:

{
int i = 0;
printf("a string");/*the code is not a working code*/
}

I believe this should be helpful:

https://www.configrouter.com/iso-c90-forbids-mixed-declarations-and-code-in-c-30621/


提交答案