PermisonError: [ Errno 13]在 Python 中

刚开始学习 Python，我遇到了一个问题，如下所述:

a_file = open('E:\Python Win7-64-AMD 3.3\Test', encoding='utf-8')


Traceback (most recent call last):
File "<pyshell#9>", line 1, in <module>
a_file = open('E:\Python Win7-64-AMD 3.3\Test', encoding='utf-8')
PermissionError: [Errno 13] Permission denied: 'E:\\Python Win7-64-AMD 3.3\\Test\

似乎是一个文件许可错误，如果任何人可以发出一些光将非常感谢。

注意: 不确定 Python 和 Windows 文件是如何工作的，但我以管理员身份登录到 Windows，该文件夹具有管理员权限。

我已经尝试将 .exe属性更改为作为 Admin 运行。

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最佳答案

When doing;

a_file = open('E:\Python Win7-64-AMD 3.3\Test', encoding='utf-8')

...you're trying to open a directory as a file, which may (and on most non UNIX file systems will) fail.

Your other example though;

a_file = open('E:\Python Win7-64-AMD 3.3\Test\a.txt', encoding='utf-8')

should work well if you just have the permission on a.txt. You may want to use a raw (r-prefixed) string though, to make sure your path does not contain any escape characters like \n that will be translated to special characters.

a_file = open(r'E:\Python Win7-64-AMD 3.3\Test\a.txt', encoding='utf-8')
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For me, I was writing to a file that is opened in Excel.

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I encountered this problem when I accidentally tried running my python module through the command prompt while my working directory was C:\Windows\System32 instead of the usual directory from which I run my python module

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For me, I got this error when I was trying to write a file to a folder and wanted to make sure the folder existed. I accidentally used:

path = Path("path/to/my/file.txt")
path.mkdir(parents=True, exist_ok=True)
with open(path, "w") as file:
...

but the second line means "make a directory at this exact path (and make its parents too, without throwing errors for them existing already)". The third line then throws a PermissionError, because you can't use open() on a directory path, of course! The second line should have been:

path.parent.mkdir(parents=True, exist_ok=True)

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