使用 jQueryDataTables 时禁用上一列的排序
我在一个项目中使用 jQueryDataTables，我想知道如何禁用最后一列的排序。我想在整个网站上实现这一点。
现在我有以下代码:
<!-- jQuery DataTable -->
<script src="../assets/js/plugins/dataTables/jquery.datatables.min.js"></script>
<script>
/* Default class modification */
$.extend( $.fn.dataTableExt.oStdClasses, {
"sWrapper": "dataTables_wrapper form-inline"
} );
/* API method to get paging information */
$.fn.dataTableExt.oApi.fnPagingInfo = function ( oSettings )
{
return {
"iStart": oSettings._iDisplayStart,
"iEnd": oSettings.fnDisplayEnd(),
"iLength": oSettings._iDisplayLength,
"iTotal": oSettings.fnRecordsTotal(),
"iFilteredTotal": oSettings.fnRecordsDisplay(),
"iPage": Math.ceil( oSettings._iDisplayStart / oSettings._iDisplayLength ),
"iTotalPages": Math.ceil( oSettings.fnRecordsDisplay() / oSettings._iDisplayLength )
};
}
/* Bootstrap style pagination control */
$.extend( $.fn.dataTableExt.oPagination, {
"bootstrap": {
"fnInit": function( oSettings, nPaging, fnDraw ) {
var oLang = oSettings.oLanguage.oPaginate;
var fnClickHandler = function ( e ) {
e.preventDefault();
if ( oSettings.oApi._fnPageChange(oSettings, e.data.action) ) {
fnDraw( oSettings );
}
};
$(nPaging).addClass('pagination').append(
'<ul>'+
'<li class="prev disabled"><a href="#">← '+oLang.sPrevious+'</a></li>'+
'<li class="next disabled"><a href="#">'+oLang.sNext+' → </a></li>'+
'</ul>'
);
var els = $('a', nPaging);
$(els[0]).bind( 'click.DT', { action: "previous" }, fnClickHandler );
$(els[1]).bind( 'click.DT', { action: "next" }, fnClickHandler );
},
"fnUpdate": function ( oSettings, fnDraw ) {
var iListLength = 5;
var oPaging = oSettings.oInstance.fnPagingInfo();
var an = oSettings.aanFeatures.p;
var i, j, sClass, iStart, iEnd, iHalf=Math.floor(iListLength/2);
if ( oPaging.iTotalPages < iListLength) {
iStart = 1;
iEnd = oPaging.iTotalPages;
}
else if ( oPaging.iPage <= iHalf ) {
iStart = 1;
iEnd = iListLength;
} else if ( oPaging.iPage >= (oPaging.iTotalPages-iHalf) ) {
iStart = oPaging.iTotalPages - iListLength + 1;
iEnd = oPaging.iTotalPages;
} else {
iStart = oPaging.iPage - iHalf + 1;
iEnd = iStart + iListLength - 1;
}
for ( i=0, iLen=an.length ; i<iLen ; i++ ) {
// Remove the middle elements
$('li:gt(0)', an[i]).filter(':not(:last)').remove();
// Add the new list items and their event handlers
for ( j=iStart ; j<=iEnd ; j++ ) {
sClass = (j==oPaging.iPage+1) ? 'class="active"' : '';
$('<li '+sClass+'><a href="#">'+j+'</a></li>')
.insertBefore( $('li:last', an[i])[0] )
.bind('click', function (e) {
e.preventDefault();
oSettings._iDisplayStart = (parseInt($('a', this).text(),10)-1) * oPaging.iLength;
fnDraw( oSettings );
} );
}
// Add / remove disabled classes from the static elements
if ( oPaging.iPage === 0 ) {
$('li:first', an[i]).addClass('disabled');
} else {
$('li:first', an[i]).removeClass('disabled');
}
if ( oPaging.iPage === oPaging.iTotalPages-1 || oPaging.iTotalPages === 0 ) {
$('li:last', an[i]).addClass('disabled');
} else {
$('li:last', an[i]).removeClass('disabled');
}
}
}
}
});
/* Show/hide table column */
function dtShowHideCol( iCol ) {
var oTable = $('#example-2').dataTable();
var bVis = oTable.fnSettings().aoColumns[iCol].bVisible;
oTable.fnSetColumnVis( iCol, bVis ? false : true );
};
/* Table #example */
$(document).ready(function() {
$('.datatable').dataTable( {
"sDom": "<'row'<'span6'l><'span6'f>r>t<'row'<'span6'i><'span6'p>>",
"sPaginationType": "bootstrap",
"oLanguage": {
"sLengthMenu": "_MENU_ records per page"
}
});
$('.datatable-controls').on('click','li input',function(){
dtShowHideCol( $(this).val() );
})
});
</script>
最佳答案