如何在 Python 中显示字符串的前几个字符？

You can 'slice' a string very easily, just like you'd pull items from a list:

a_string = 'This is a string'

To get the first 4 letters:

first_four_letters = a_string[:4]
>>> 'This'

Or the last 5:

last_five_letters = a_string[-5:]
>>> 'string'

So applying that logic to your problem:

the_string = '416d76b8811b0ddae2fdad8f4721ddbe|d4f656ee006e248f2f3a8a93a8aec5868788b927|12a5f648928f8e0b5376d2cc07de8e4cbf9f7ccbadb97d898373f85f0a75c47f '
first_32_chars = the_string[:32]
>>> 416d76b8811b0ddae2fdad8f4721ddbe

Since there is a delimiter, you should use that instead of worrying about how long the md5 is.

>>> s = "416d76b8811b0ddae2fdad8f4721ddbe|d4f656ee006e248f2f3a8a93a8aec5868788b927|12a5f648928f8e0b5376d2cc07de8e4cbf9f7ccbadb97d898373f85f0a75c47f"
>>> md5sum, delim, rest = s.partition('|')
>>> md5sum
'416d76b8811b0ddae2fdad8f4721ddbe'

Alternatively

>>> md5sum, sha1sum, sha5sum = s.split('|')
>>> md5sum
'416d76b8811b0ddae2fdad8f4721ddbe'
>>> sha1sum
'd4f656ee006e248f2f3a8a93a8aec5868788b927'
>>> sha5sum
'12a5f648928f8e0b5376d2cc07de8e4cbf9f7ccbadb97d898373f85f0a75c47f'

If you want first 2 letters and last 2 letters of a string then you can use the following code: name = "India" name[0:2]="In" names[-2:]="ia"