我如何才能有所有用户登录(通过春季安全)我的 Web 应用程序的列表

小开

最佳答案

For accessing the list of all logged in users you need to inject SessionRegistry instance to your bean.

@Autowired
@Qualifier("sessionRegistry")
private SessionRegistry sessionRegistry;

And then using injcted SessionRegistry you can access the list of all principals:

List<Object> principals = sessionRegistry.getAllPrincipals();


List<String> usersNamesList = new ArrayList<String>();


for (Object principal: principals) {
if (principal instanceof User) {
usersNamesList.add(((User) principal).getUsername());
}
}

But before injecting session registry you need to define session management part in your spring-security.xml (look at Session Management section in Spring Security reference documentation) and in concurrency-control section you should set alias for session registry object (session-registry-alias) by which you will inject it.

    <security:http access-denied-page="/error403.jsp" use-expressions="true" auto-config="false">
<security:session-management session-fixation-protection="migrateSession" session-authentication-error-url="/login.jsp?authFailed=true">
<security:concurrency-control max-sessions="1" error-if-maximum-exceeded="true" expired-url="/login.html" session-registry-alias="sessionRegistry"/>
</security:session-management>


...
</security:http>

小开

In JavaConfig, it would look like this:

@Configuration
@EnableWebSecurity
public class SecurityConfig extends WebSecurityConfigurerAdapter {
@Override
protected void configure(final HttpSecurity http) throws Exception {
// ...
http.sessionManagement().maximumSessions(1).sessionRegistry(sessionRegistry());
}


@Bean
public SessionRegistry sessionRegistry() {
return new SessionRegistryImpl();
}


@Bean
public ServletListenerRegistrationBean<HttpSessionEventPublisher> httpSessionEventPublisher() {
return new ServletListenerRegistrationBean<HttpSessionEventPublisher>(new HttpSessionEventPublisher());
}
}

With the calling code looking like this:

public class UserController {
@Autowired
private SessionRegistry sessionRegistry;


public void listLoggedInUsers() {
final List<Object> allPrincipals = sessionRegistry.getAllPrincipals();


for(final Object principal : allPrincipals) {
if(principal instanceof SecurityUser) {
final SecurityUser user = (SecurityUser) principal;


// Do something with user
System.out.println(user);
}
}
}
}

Note that SecurityUser is my own class which implements UserDetails.

小开

Please correct me if I'm wrong.

I think @Adam's answer is incomplete. I noticed that sessions already expired in the list were appearing again.

public class UserController {
@Autowired
private SessionRegistry sessionRegistry;


public void listLoggedInUsers() {
final List<Object> allPrincipals = sessionRegistry.getAllPrincipals();


for (final Object principal : allPrincipals) {
if (principal instanceof SecurityUser) {
final SecurityUser user = (SecurityUser) principal;


List<SessionInformation> activeUserSessions =
sessionRegistry.getAllSessions(principal,
/* includeExpiredSessions */ false); // Should not return null;


if (!activeUserSessions.isEmpty()) {
// Do something with user
System.out.println(user);
}
}
}
}
}

Hope it helps.

小开

Please correct me if I'm wrong too.

I think @Adam's and @elysch`s answer is incomplete. I noticed that there are needed to add listener:

 servletContext.addListener(HttpSessionEventPublisher.class);

to

public class AppInitializer implements WebApplicationInitializer {


@Override
public void onStartup(ServletContext servletContext) {
...
servletContext.addListener(HttpSessionEventPublisher.class);
}

with security conf:

@Configuration
@EnableWebSecurity
public class SecurityConfig extends WebSecurityConfigurerAdapter {
@Override
protected void configure(final HttpSecurity http) throws Exception {
// ...
http.sessionManagement().maximumSessions(1).sessionRegistry(sessionRegistry());
}


@Bean
public SessionRegistry sessionRegistry() {
return new SessionRegistryImpl();
}


@Bean
public HttpSessionEventPublisher httpSessionEventPublisher() {
return new HttpSessionEventPublisher();
}
}

And then you will get current online users!

小开

You need to inject SessionRegistry (as mentioned eariler) and then you can do it in one pipeline like this:

public List<UserDetails> findAllLoggedInUsers() {
return sessionRegistry.getAllPrincipals()
.stream()
.filter(principal -> principal instanceof UserDetails)
.map(UserDetails.class::cast)
.collect(Collectors.toList());
}

小开

Found this note to be quite important and relevant:

"[21] Authentication by mechanisms which perform a redirect after authenticating (such as form-login) will not be detected by SessionManagementFilter, as the filter will not be invoked during the authenticating request. Session-management functionality has to be handled separately in these cases."

https://docs.spring.io/spring-security/site/docs/3.1.x/reference/session-mgmt.html#d0e4399

Also, apparently a lot of people have troubles getting sessionRegistry.getAllPrincipals() returning something different from an empty array. In my case, I fixed it by adding the sessionAuthenticationStrategy to my custom authenticationFilter:

@Bean
public CustomUsernamePasswordAuthenticationFilter authenticationFilter() throws Exception {
...


authenticationFilter.setSessionAuthenticationStrategy(sessionAuthenticationStrategy());
}


@Bean
public SessionRegistry sessionRegistry() {
return new SessionRegistryImpl();
}


//cf. https://stackoverflow.com/questions/32463022/sessionregistry-is-empty-when-i-use-concurrentsessioncontrolauthenticationstrate
public SessionAuthenticationStrategy sessionAuthenticationStrategy() {
List<SessionAuthenticationStrategy> stratList = new ArrayList<>();
SessionFixationProtectionStrategy concStrat = new SessionFixationProtectionStrategy();
stratList.add(concStrat);
RegisterSessionAuthenticationStrategy regStrat = new RegisterSessionAuthenticationStrategy(sessionRegistry());
stratList.add(regStrat);
CompositeSessionAuthenticationStrategy compStrat = new CompositeSessionAuthenticationStrategy(stratList);
return compStrat;
}

小开

Similar to @rolyanos solution, mine for me always works:

- for the controller

@RequestMapping(value = "/admin")
public String admin(Map<String, Object> model) {


if(sessionRegistry.getAllPrincipals().size() != 0) {
logger.info("ACTIVE USER: " + sessionRegistry.getAllPrincipals().size());
model.put("activeuser",  sessionRegistry.getAllPrincipals().size());
}
else
logger.warn("EMPTY" );


logger.debug(log_msg_a + " access ADMIN page. Access granted." + ANSI_RESET);
return "admin";
}

- for the front end

<tr th:each="activeuser, iterStat: ${activeuser}">
<th><b>Active users: </b></th> <td align="center" th:text="${activeuser}"></td>
</tr>

- for spring confing

@Bean
public SessionRegistry sessionRegistry() {
return new SessionRegistryImpl();
}


@Bean
public ServletListenerRegistrationBean<HttpSessionEventPublisher> httpSessionEventPublisher() {
return new ServletListenerRegistrationBean<HttpSessionEventPublisher>(new HttpSessionEventPublisher());
}




@Override
protected void configure(HttpSecurity http) throws Exception {


http.logout()
.logoutSuccessUrl("/home")
.logoutUrl("/logout")
.invalidateHttpSession(true)
.deleteCookies("JSESSIONID");




http.authorizeRequests()
.antMatchers("/", "/home")
.permitAll()


.antMatchers("/admin")
.hasRole("ADMIN")
.anyRequest()
.authenticated()


.and()
.formLogin()
.loginPage("/home")
.defaultSuccessUrl("/main")
.permitAll()
.and()
.logout()
.permitAll();


http.sessionManagement().maximumSessions(1).sessionRegistry(sessionRegistry());


http.authorizeRequests().antMatchers("/webjars/**").permitAll();


http.exceptionHandling().accessDeniedPage("/403");
}