是否可以等到所有的 javascript 文件都加载完毕后再执行 javascript 代码？

You can use <script>'s defer attribute. It specifies that the script will be executed when the page has finished parsing.

<script defer src="path/to/yourscript.js">

A nice article about this: http://davidwalsh.name/script-defer

Browser support seems pretty good: http://caniuse.com/#search=defer

Another great article about loading JS using defer and async: https://flaviocopes.com/javascript-async-defer/

You can use

$(window).on('load', function() {
// your code here
});

Which will wait until the page is loaded. $(document).ready() waits until the DOM is loaded.

In plain JS:

window.addEventListener('load', function() {
// your code here
})

You can use .getScript() and run your code after it loads:

 $.getScript("my_lovely_script.js", function(){


alert("Script loaded and executed.");
// here you can use anything you defined in the loaded script


});

You can see a better explanation here: How do I include a JavaScript file in another JavaScript file?

Expanding a bit on @Eruant's answer,

$(window).on('load', function() {
// your code here
});

Works very well with both async and defer while loading on scripts.

So you can import all scripts like this:

<script src="/js/script1.js" async defer></script>
<script src="/js/script2.js" async defer></script>
<script src="/js/script3.js" async defer></script>

Just make sure script1 doesn't call functions from script3 before $(window).on('load' ..., make sure to call them inside window load event.

More about async/defer here.

Thats work for me:

var jsScripts = [];


jsScripts.push("/js/script1.js" );
jsScripts.push("/js/script2.js" );
jsScripts.push("/js/script3.js" );


$(jsScripts).each(function( index, value ) {
$.holdReady( true );
$.getScript( value ).done(function(script, status) {
console.log('Loaded ' + index + ' : ' + value + ' (' + status + ')');
$.holdReady( false );
});
});