在 Oracle SQL 中计算2个日期/时间之间的差异

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You can substract dates in Oracle. This will give you the difference in days. Multiply by 24 to get hours, and so on.

SQL> select oldest - creation from my_table;

If your date is stored as character data, you have to convert it to a date type first.

SQL> select 24 * (to_date('2009-07-07 22:00', 'YYYY-MM-DD hh24:mi')
- to_date('2009-07-07 19:30', 'YYYY-MM-DD hh24:mi')) diff_hours
from dual;


DIFF_HOURS
----------
2.5

Note:

This answer applies to dates represented by the Oracle data type DATE. Oracle also has a data type TIMESTAMP, which can also represent a date (with time). If you subtract TIMESTAMP values, you get an INTERVAL; to extract numeric values, use the EXTRACT function.

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You could use to_timestamp function to convert the dates to timestamps and perform a substract operation.

Something like:

SELECT
TO_TIMESTAMP ('13.10.1990 00:00:00','DD.MM.YYYY HH24:MI:SS')  -
TO_TIMESTAMP ('01.01.1990:00:10:00','DD.MM.YYYY:HH24:MI:SS')
FROM DUAL

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$sql="select bsp_bp,user_name,status,
to_char(ins_date,'dd/mm/yyyy hh12:mi:ss AM'),
to_char(pickup_date,'dd/mm/yyyy hh12:mi:ss AM'),
trunc((pickup_date-ins_date)*24*60*60,2),message,status_message
from valid_bsp_req where id >= '$id'";

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Calculate age from HIREDATE to system date of your computer

SELECT HIREDATE||'        '||SYSDATE||'       ' ||
TRUNC(MONTHS_BETWEEN(SYSDATE,HIREDATE)/12) ||' YEARS '||
TRUNC((MONTHS_BETWEEN(SYSDATE,HIREDATE))-(TRUNC(MONTHS_BETWEEN(SYSDATE,HIREDATE)/12)*12))||
'MONTHS' AS "AGE  "  FROM EMP;

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declare
strTime1 varchar2(50) := '02/08/2013 01:09:42 PM';
strTime2 varchar2(50) := '02/08/2013 11:09:00 PM';
v_date1 date := to_date(strTime1,'DD/MM/YYYY HH:MI:SS PM');
v_date2 date := to_date(strTime2,'DD/MM/YYYY HH:MI:SS PM');
difrence_In_Hours number;
difrence_In_minutes number;
difrence_In_seconds number;
begin
difrence_In_Hours   := (v_date2 - v_date1) * 24;
difrence_In_minutes := difrence_In_Hours * 60;
difrence_In_seconds := difrence_In_minutes * 60;


dbms_output.put_line(strTime1);
dbms_output.put_line(strTime2);
dbms_output.put_line('*******');
dbms_output.put_line('difrence_In_Hours  : ' || difrence_In_Hours);
dbms_output.put_line('difrence_In_minutes: ' || difrence_In_minutes);
dbms_output.put_line('difrence_In_seconds: ' || difrence_In_seconds);
end ;

Hope this helps.

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This will count time between to dates:

SELECT
(TO_CHAR( TRUNC (ROUND(((sysdate+1) - sysdate)*24,2))*60,'999999')
+
TO_CHAR(((((sysdate+1)-sysdate)*24)- TRUNC(ROUND(((sysdate+1) - sysdate)*24,2)))/100*60 *100, '09'))/60
FROM dual

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Here's another option:

with tbl_demo AS
(SELECT TO_DATE('11/26/2013 13:18:50', 'MM/DD/YYYY HH24:MI:SS') dt1
, TO_DATE('11/28/2013 21:59:12', 'MM/DD/YYYY HH24:MI:SS') dt2
FROM dual)
SELECT dt1
, dt2
, round(dt2 - dt1,2) diff_days
, round(dt2 - dt1,2)*24 diff_hrs
, numtodsinterval((dt2 - dt1),'day') diff_dd_hh_mm_ss
from tbl_demo;

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select days||' '|| time from (
SELECT to_number( to_char(to_date('1','J') +
(CLOSED_DATE - CREATED_DATE), 'J') - 1)  days,
to_char(to_date('00:00:00','HH24:MI:SS') +
(CLOSED_DATE - CREATED_DATE), 'HH24:MI:SS') time
FROM  request  where REQUEST_ID=158761088 );

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select (floor(((DATE2-DATE1)*24*60*60)/3600)|| ' : ' ||floor((((DATE2-DATE1)*24*60*60) -floor(((DATE2-DATE1)*24*60*60)/3600)*3600)/60)|| '  ' ) as time_difference from TABLE1

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select
extract( day from diff ) Days,
extract( hour from diff ) Hours,
extract( minute from diff ) Minutes
from (
select (CAST(creationdate as timestamp) - CAST(oldcreationdate as timestamp)) diff
from [TableName]
);

This will give you three columns as Days, Hours and Minutes.

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You may also try this:

select to_char(to_date('1970-01-01 00:00:00', 'yyyy-mm-dd hh24:mi:ss')+(end_date - start_date),'hh24:mi:ss')
as run_time from some_table;

It displays time in more human readable form, like: 00:01:34. If you need also days you may simply add DD to last formatting string.

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In oracle 11g

SELECT end_date - start_date AS day_diff FROM tablexxx
suppose the starT_date end_date is define in the tablexxx

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To get result in seconds:

select (END_DT - START_DT)*60*60*24 from MY_TABLE;

Check [https://community.oracle.com/thread/2145099?tstart=0][1]

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If you want something that looks a bit simpler, try this for finding events in a table which occurred in the past 1 minute:

With this entry you can fiddle with the decimal values till you get the minute value that you want. The value .0007 happens to be 1 minute as far as the sysdate significant digits are concerned. You can use multiples of that to get any other value that you want:

select (sysdate - (sysdate - .0007)) * 1440 from dual;

Result is 1 (minute)

Then it is a simple matter to check for

select * from my_table where (sysdate - transdate) < .00071;

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(TO_DATE(:P_comapre_date_1, 'dd-mm-yyyy hh24:mi') - TO_DATE(:P_comapre_date_2, 'dd-mm-yyyy hh24:mi'))*60*60*24 sum_seconds,
(TO_DATE(:P_comapre_date_1, 'dd-mm-yyyy hh24:mi') - TO_DATE(:P_comapre_date_2, 'dd-mm-yyyy hh24:mi'))*60*24 sum_minutes,
(TO_DATE(:P_comapre_date_1, 'dd-mm-yyyy hh24:mi') - TO_DATE(:P_comapre_date_2, 'dd-mm-yyyy hh24:mi'))*24 sum_hours,
(TO_DATE(:P_comapre_date_1, 'dd-mm-yyyy hh24:mi') - TO_DATE(:P_comapre_date_2, 'dd-mm-yyyy hh24:mi')) sum_days

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If you select two dates from 'your_table' and want too see the result as a single column output (eg. 'days - hh:mm:ss') you could use something like this. First you could calculate the interval between these two dates and after that export all the data you need from that interval:

         select     extract (day from numtodsinterval (second_date
- add_months (created_date,
floor (months_between (second_date,created_date))),
'day'))
|| ' days - '
|| extract (hour from numtodsinterval (second_date
- add_months (created_date,
floor (months_between (second_date,created_date))),
'day'))
|| ':'
|| extract (minute from numtodsinterval (second_date
- add_months (created_date,
floor (months_between (second_date, created_date))),
'day'))
|| ':'
|| extract (second from numtodsinterval (second_date
- add_months (created_date,
floor (months_between (second_date, created_date))),
'day'))
from    your_table

And that should give you result like this: 0 days - 1:14:55

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Single query that will return time difference of two timestamp columns:

select INS_TS, MAIL_SENT_TS, extract( hour from (INS_TS - MAIL_SENT_TS) ) timeDiff
from MAIL_NOTIFICATIONS;

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If You want get date defer from using table and column.

SELECT TO_DATE( TO_CHAR(COLUMN_NAME_1, 'YYYY-MM-DD'), 'YYYY-MM-DD') -
TO_DATE(TO_CHAR(COLUMN_NAME_2, 'YYYY-MM-DD') , 'YYYY-MM-DD')  AS DATEDIFF
FROM TABLE_NAME;

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select to_char(actual_start_date,'DD-MON-YYYY hh24:mi:ss') start_time,
to_char(actual_completion_date,'DD-MON-YYYY hh24:mi:ss') end_time,
floor((actual_completion_date-actual_start_date)*24*60)||'.'||round(mod((actual_completion_date-actual_start_date)*24*60*60,60)) diff_time
from fnd_concurrent_requests
order by request_id desc;

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select round( (tbl.Todate - tbl.fromDate) * 24 * 60 * 60 ) from table tbl

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for oracle sql I justbn did this and works perfect :

SELECT trunc(date_col_1) -  trunc(date_col_2)
FROM   TABLE;