用 java 按钮在浏览器中打开链接?

如何在默认浏览器中按一下按钮打开一个链接

button.addActionListener(new ActionListener() {
public void actionPerformed(ActionEvent e) {
open("www.google.com"); // just what is the 'open' method?
}
});

155746 次浏览

Use the Desktop#browse(URI) method. It opens a URI in the user's default browser.

public static boolean openWebpage(URI uri) {
Desktop desktop = Desktop.isDesktopSupported() ? Desktop.getDesktop() : null;
if (desktop != null && desktop.isSupported(Desktop.Action.BROWSE)) {
try {
desktop.browse(uri);
return true;
} catch (Exception e) {
e.printStackTrace();
}
}
return false;
}


public static boolean openWebpage(URL url) {
try {
return openWebpage(url.toURI());
} catch (URISyntaxException e) {
e.printStackTrace();
}
return false;
}
public static void openWebpage(String urlString) {
try {
Desktop.getDesktop().browse(new URL(urlString).toURI());
} catch (Exception e) {
e.printStackTrace();
}
}
try {
Desktop.getDesktop().browse(new URL("http://www.google.com").toURI());
} catch (Exception e) {}

note: you have to include necessary imports from java.net

A solution without the Desktop environment is BrowserLauncher2. This solution is more general as on Linux, Desktop is not always available.

The lenghty answer is posted at https://stackoverflow.com/a/21676290/873282

private void ButtonOpenWebActionPerformed(java.awt.event.ActionEvent evt) {
try {
String url = "https://www.google.com";
java.awt.Desktop.getDesktop().browse(java.net.URI.create(url));
} catch (java.io.IOException e) {
System.out.println(e.getMessage());
}
}
public static void openWebPage(String url) {
try {
Desktop desktop = Desktop.isDesktopSupported() ? Desktop.getDesktop() : null;
if (desktop != null && desktop.isSupported(Desktop.Action.BROWSE)) {
desktop.browse(new URI(url));
}
throw new NullPointerException();
} catch (Exception e) {
JOptionPane.showMessageDialog(null, url, "", JOptionPane.PLAIN_MESSAGE);
}
}

I know that this is an old question but sometimes the Desktop.getDesktop() produces an unexpected crash like in Ubuntu 18.04. Therefore, I have to re-write my code like this:

public static void openURL(String domain)
{
String url = "https://" + domain;
Runtime rt = Runtime.getRuntime();
try {
if (MUtils.isWindows()) {
rt.exec("rundll32 url.dll,FileProtocolHandler " + url).waitFor();
Debug.log("Browser: " + url);
} else if (MUtils.isMac()) {
String[] cmd = {"open", url};
rt.exec(cmd).waitFor();
Debug.log("Browser: " + url);
} else if (MUtils.isUnix()) {
String[] cmd = {"xdg-open", url};
rt.exec(cmd).waitFor();
Debug.log("Browser: " + url);
} else {
try {
throw new IllegalStateException();
} catch (IllegalStateException e1) {
MUtils.alertMessage(Lang.get("desktop.not.supported"), MainPn.getMainPn());
e1.printStackTrace();
}
}
} catch (IOException | InterruptedException e) {
e.printStackTrace();
}
}


public static boolean isWindows()
{
return OS.contains("win");
}


public static boolean isMac()
{
return OS.contains("mac");
}


public static boolean isUnix()
{
return OS.contains("nix") || OS.contains("nux") || OS.indexOf("aix") > 0;
}

Then we can call this helper from the instance:

button.addActionListener(new ActionListener() {
public void actionPerformed(ActionEvent e) {
MUtils.openURL("www.google.com"); // just what is the 'open' method?
}
});