How to deserialize xml to object

你的课应该是这样的

[XmlRoot("StepList")]
public class StepList
{
[XmlElement("Step")]
public List<Step> Steps { get; set; }
}


public class Step
{
[XmlElement("Name")]
public string Name { get; set; }
[XmlElement("Desc")]
public string Desc { get; set; }
}

这是我的测试代码。

string testData = @"<StepList>
<Step>
<Name>Name1</Name>
<Desc>Desc1</Desc>
</Step>
<Step>
<Name>Name2</Name>
<Desc>Desc2</Desc>
</Step>
</StepList>";


XmlSerializer serializer = new XmlSerializer(typeof(StepList));
using (TextReader reader = new StringReader(testData))
{
StepList result = (StepList) serializer.Deserialize(reader);
}

如果要读取文本文件，应该将该文件加载到 FileStream 中 把这个反序列化。

using (FileStream fileStream = new FileStream("<PathToYourFile>", FileMode.Open))
{
StepList result = (StepList) serializer.Deserialize(fileStream);
}

上面的评论是正确的。你错过了装饰。 如果需要泛型反序列化器，可以使用。

public static T DeserializeXMLFileToObject<T>(string XmlFilename)
{
T returnObject = default(T);
if (string.IsNullOrEmpty(XmlFilename)) return default(T);


try
{
StreamReader xmlStream = new StreamReader(XmlFilename);
XmlSerializer serializer = new XmlSerializer(typeof(T));
returnObject = (T)serializer.Deserialize(xmlStream);
}
catch (Exception ex)
{
ExceptionLogger.WriteExceptionToConsole(ex, DateTime.Now);
}
return returnObject;
}

然后你会这样称呼它:

MyObjType MyObj = DeserializeXMLFileToObject<MyObjType>(FilePath);