如何在JRuby中将浮点数四舍五入到小数点后2位？

如何在JRuby（1.6.X）中将浮点数四舍五入到小数点后2位？

number = 1.1164
number.round(2)


# The above shows the following error
# wrong number of arguments (1 for 0)
283556 次浏览
小开
最佳答案

Float#round can take a parameter in Ruby 1.9, not in Ruby 1.8. JRuby defaults to 1.8, but it is capable of running in 1.9 mode.

小开

sprintf('%.2f', number) is a cryptic, but very powerful way of formatting numbers. The result is always a string, but since you're rounding I assume you're doing it for presentation purposes anyway. sprintf can format any number almost any way you like, and lots more.

Full sprintf documentation: http://www.ruby-doc.org/core-2.0.0/Kernel.html#method-i-sprintf

小开 
(5.65235534).round(2)
#=> 5.65
小开

to truncate a decimal I've used the follow code:

<th><%#= sprintf("%0.01f",prom/total) %><!--1dec,aprox-->
<% if prom == 0 or total == 0 %>
N.E.
<% else %>
<%= Integer((prom/total).to_d*10)*0.1 %><!--1decimal,truncado-->
<% end %>
<%#= prom/total %>
</th>

If you want to truncate to 2 decimals, you should use Integr(a*100)*0.01

小开

Edit

After getting feedback, It seems the original solution didn't work. That's why updated the answer as one of the suggestions.

def float_of_2_decimal(float_n)
float_n.to_d.round(2, :truncate).to_f
end

Other answers may work, if you want to have rounded numbers of 2 decimal places. But, If you want to have floating point numbers with first two decimal places without rounding, Those answers won't help.

So, to get a floating point number with first two decimal places, I used this technique. Doesn't work in some cases

def float_of_2_decimal(float_n)
float_n.round(3).to_s[0..3].to_f
end

with 5.666666666666666666666666, it will return 5.66 instead of rounded 5.67. Hope it will help someone

小开

Try this:

module Util
module MyUtil






def self.redondear_up(suma,cantidad, decimales=0)


unless suma.present?
return nil
end




if suma>0
resultado= (suma.to_f/cantidad)
return resultado.round(decimales)
end




return nil




end


end
end

提交答案