SQL内部连接3个表?

我试图在视图中连接3个表;情况是这样的:

我有一张表格，上面有申请在这所大学校园居住的学生的信息。我有另一个表，列出了每个学生的大厅偏好(其中3个)。但是每个参数都只是一个ID Number，并且ID Number在第三个表中有一个对应的Hall Name(没有设计这个数据库…)。

基本上，我在表中有INNER JOIN和它们的首选项，以及它们的信息，结果是这样的……

 John Doe | 923423 | Incoming Student | 005

其中005将是HallID。所以现在我想将这个HallID匹配到第三个表，这个表包含HallID和HallName。

所以，我希望结果是这样的。

 John Doe | 923423 | Incoming Student | Foley Hall <---(INSTEAD OF 005)

以下是我目前拥有的:

SELECT
s.StudentID, s.FName,
s.LName, s.Gender, s.BirthDate, s.Email,
r.HallPref1, r.HallPref2, r.HallPref3
FROM
dbo.StudentSignUp AS s
INNER JOIN RoomSignUp.dbo.Incoming_Applications_Current AS r
ON s.StudentID = r.StudentID
INNER JOIN HallData.dbo.Halls AS h
ON r.HallPref1 = h.HallID
1545511 次浏览
小开

如果你有3个具有相同ID的表要连接，我认为它会像这样:

SELECT * FROM table1 a
JOIN table2 b ON a.ID = b.ID
JOIN table3 c ON a.ID = c.ID

只需将*替换为您想从表中获取的内容。

小开

你只需要第二个内部连接，将你现在拥有的ID Number连接到第三个表的ID Number。之后，将ID Number替换为Hall Name和voilá:)

小开
最佳答案

您可以执行以下操作(我猜是在表字段等上)

SELECT s.studentname
, s.studentid
, s.studentdesc
, h.hallname
FROM students s
INNER JOIN hallprefs hp
on s.studentid = hp.studentid
INNER JOIN halls h
on hp.hallid = h.hallid

根据你对多个大厅的要求，你可以这样做。您只需为每个房间加入您的大厅桌子多次:

SELECT     s.StudentID
, s.FName
, s.LName
, s.Gender
, s.BirthDate
, s.Email
, r.HallPref1
, h1.hallName as Pref1HallName
, r.HallPref2
, h2.hallName as Pref2HallName
, r.HallPref3
, h3.hallName as Pref3HallName
FROM  dbo.StudentSignUp AS s
INNER JOIN RoomSignUp.dbo.Incoming_Applications_Current AS r
ON s.StudentID = r.StudentID
INNER JOIN HallData.dbo.Halls AS h1
ON r.HallPref1 = h1.HallID
INNER JOIN HallData.dbo.Halls AS h2
ON r.HallPref2 = h2.HallID
INNER JOIN HallData.dbo.Halls AS h3
ON r.HallPref3 = h3.HallID
小开 
SELECT column_Name1,column_name2,......
From tbl_name1,tbl_name2,tbl_name3
where tbl_name1.column_name = tbl_name2.column_name
and tbl_name2.column_name = tbl_name3.column_name
小开

这是对id相同的连接3表的正确查询

select a.empname,a.empsalary,b.workstatus,b.bonus,c.dateofbirth from employee a, Report b,birth c where a.empid=b.empid and a.empid=c.empid and b.empid='103';

员工第一表。 报告第二表。 出生第三表

小开 
select empid,empname,managename,[Management ],cityname
from employees inner join Managment
on employees.manageid = Managment.ManageId
inner join CITY on employees.Cityid=CITY.CityId




id name  managename  managment  cityname
----------------------------------------
1  islam   hamza       it        cairo
小开 
SELECT table1.col,table2.col,table3.col
FROM table1
INNER JOIN
(table2 INNER JOIN table3
ON table3.id=table2.id)
ON table1.id(f-key)=table2.id
AND //add any additional filters HERE
小开 
SELECT *
FROM
PersonAddress a,
Person b,
PersonAdmin c
WHERE a.addressid LIKE '97%'
AND b.lastname LIKE 'test%'
AND b.genderid IS NOT NULL
AND a.partyid = c.partyid
AND b.partyid = c.partyid;
小开 
SELECT
A.P_NAME AS [INDIVIDUAL NAME],B.F_DETAIL AS [INDIVIDUAL FEATURE],C.PL_PLACE AS [INDIVIDUAL LOCATION]
FROM
[dbo].[PEOPLE] A
INNER JOIN
[dbo].[FEATURE] B ON A.P_FEATURE = B.F_ID
INNER JOIN
[dbo].[PEOPLE_LOCATION] C ON A.P_LOCATION = C.PL_ID
小开

这个查询将为您工作

Select b.id as 'id', u.id as 'freelancer_id', u.name as
'free_lancer_name', p.user_id as 'project_owner', b.price as
'bid_price', b.number_of_days as 'days' from User u, Project p, Bid b
where b.user_id = u.id and b.project_id = p.id
小开

已经有很多回应，但总的教训似乎是，你可以在一个where子句中使用多个join;还有techonthenet.com(我的老板推荐给我的，这就是我找到它的原因)有很好的SQL教程，如果你有另一个问题，你只是想尝试解决它。

SELECT table1.column1
FROM table1
WHERE table1 > 0 (or whatever you want to specify)
INNER JOIN table1
ON table1.column1 = table2.column1
小开 
select products.product_id, product_name, price, created_at, image_name, categories.category_id, category_name,brands.brand_id, brand_name
FROM products INNER JOIN categories USING (category_id) INNER JOIN brands USING(brand_id)

提交答案